Saturday, September 18, 2010

Review 9/17/10

In class on Friday we spent the majority of the time reviewing previous chapters before the test. Here are some of the problems and concepts that we went over.

Probability Concepts:

Combinations: When the order of selections doesn't matter.
You can find the total number of outcomes in a combination using nCr, nCr means the number of n items chosen r at a time. You can find the number of outcomes by setting nCr equal to
                                                                                                             

Example:  5C3 =  gif.latex.gif= gif.latex.gif=gif.latex.gif= 10, 10 is the number of possible outcomes for the situation
Permutations: When the order of selections matters

Review Problems:












































































































P(point chosen lands in white)














































































































































































































































































Area(white)= 1
π - 4π




















































































































































































































































































































































































































































































































































































































































































































































































            
                    =12pi
12
π / 36
π = 1/3  (Area of color/Area of white)




































































































































P=1/3
Area of Square= 36
Area of Circle= 9
π







Area of Light Blue= 36-9
π






P(within 5 of C)= 9/12
                           = 3/4

(Sorry that the end of the problem got cut off but point B is at 15)
Thanks for reading my blog post and I'm sorry for any inconveniences in the lineup of problems and equations! And I don't know why the circle problem got all spaced out but I can't fix it sorry.
                           -Corin Murphy
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1 comment:

  1. Corin MurphySeptember 18, 2010 at 6:08 PM

    sorry about the spaces its just messed up for some reason.

    ReplyDelete

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